KTGMedium
Question
The average kinetic energy of a gas molecule at 27oC is 6.21 × 10-21J, then its average kinetc energy at 227oC is :
Options
A.10.35 × 10-21 J
B.11.35 × 10-21 J
C.52.2 × 10-21 J
D.5.22 × 10-21 J
Solution
Average kinetic energy of gas molecules ∝ Temperature (Absolute)
K.E.(227o) =
× 6.21 × 10-21 J
= 10.35 × 10-21
K.E.(227o) =
× 6.21 × 10-21 J= 10.35 × 10-21
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