ThermodynamicsHard
Question
The average kinetic energy of a gas molecule at 27oC is 6.21 × 10-21J, then its average kinetc energy at 227oC is :
Options
A.10.35 × 10-21 J
B.11.35 × 10-21 J
C.52.2 × 10-21 J
D.5.22 × 10-21 J
Solution
Average kinetic energy of gas molecules ∝ Temperature (Absolute)
K.E.(227o) =
× 6.21 × 10-21 J
= 10.35 × 10-21
K.E.(227o) =
× 6.21 × 10-21 J= 10.35 × 10-21
Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
A system is taken from its initial state (P1, V1) to a state (P2, V2). If the heat given to the system is ᐃQ and t...An amount Q of heat is added to a monoatomic ideal gas in thermodynamic process. In the process gas expands and does Q/2...Heat is released by the gas in the process CD. n moles of a monoatomic gas undergoes a cyclic process ABCDA as shown. Pr...The wavelength of maximum energy released during an atomic explosin was 2.93 × 10-10m. The maximum temperature atta...Two bodies A and B have thermal emissivities of 0.01 and 0.81 respectively. The outer surface area of the two bodies are...