Properties of matterMedium
Question
Two small drops of mercury, each of radius R coalesece to form a single large energies before and after the change is :
Options
A.1 : 21/3
B.21/3 : 1
C.2 : 1
D.1 : 2
Solution
Let r be radius of common drop
πr3 = 2 × πR3
r = (2)-/3R
Surface energy before the coalesce
= 2 × 4πR2r
Surface energy after the coalesece = 4πr2T
Ratio =
πr3 = 2 × πR3r = (2)-/3R
Surface energy before the coalesce
= 2 × 4πR2r
Surface energy after the coalesece = 4πr2T
Ratio =
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