AIPMT | 2014Photoelectric EffectMedium
Question
When the energy of the incident radiation is increased by 20%, the kinetic energy of the photoelectrons emitted from a metal surface increased from 0.5 eV to 0.8 eV. The work function of the metal is
Options
A.0.65 eV
B.1.0 eV
C.1.3 eV
D.1.5 eV
Solution
E = hv - φ
⇒ 0.5 = hv - φ .....(1)
Again 0.8 = 1.2 hv - φ .....(2)
From equation (1) × 1.2 ⇒ 0.6 = 1.2 hv - 1.2φ
Equation (2) 0.8 = 1.2 hv - φ
- - +
- 0.2 = - 0.2 φ
φ = 1eV
⇒ 0.5 = hv - φ .....(1)
Again 0.8 = 1.2 hv - φ .....(2)
From equation (1) × 1.2 ⇒ 0.6 = 1.2 hv - 1.2φ
Equation (2) 0.8 = 1.2 hv - φ
- - +
- 0.2 = - 0.2 φ
φ = 1eV
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