Momentum and CollisionHard
Question
A solid sphere is rolling on a frictionless surface, shown in figure with a translation velocity v m/s. If it is to climb the inclined surface then v should be :
Options
A.
B.
C.2 gh
D.
Solution
Applying law of conservation of energy for roting body,
MV2 + Iω2 = mgh
MV2 + 
mr2 × 
= mgh
= gh
gh ⇒ v2 = 
v
MV2 + Iω2 = mghMV2 + mr2 × = mgh = ghgh ⇒ v2 = v
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