A particle of mass 4m which is at rest explodes into masers m, m& 2m. Two of the fragments of masses

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A particle of mass 4m which is at rest explodes into masers m, m& 2m. Two of the fragments of masses m and 2m are found to move with equal speeds v each in opposite directions. The total mechanical energy m and 2m are found to move with equal speeds each in opposite directions. The total mechanical energy released in the proses of explosion is

Accepted Answer

0 = 2mv - mv + mv&#8242; v&#8242; = - vTotal mechanical energy released = (m + m + 2m)v2 = 2mv2.

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