Momentum and CollisionHard
Question
A particle of mass 4m which is at rest explodes into masers m, m& 2m. Two of the fragments of masses m and 2m are found to move with equal speeds v each in opposite directions. The total mechanical energy m and 2m are found to move with equal speeds each in opposite directions. The total mechanical energy released in the proses of explosion is
Options
A.mv2
B.2mv2
C.1 / 2mv2
D.4mv2
Solution
0 = 2mv - mv + mv′ v′ = - v
Total mechanical energy released
=
(m + m + 2m)v2 = 2mv2.Create a free account to view solution
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