Momentum and CollisionHard
Question
A constant torque of 31.4 Nm is exerted on a pivoed wheel. If the angular acceleration of the wheel is 4π rad/ sec2, then the moment of inertia will be:
Options
A.5.8kg - m2
B.4.5kg - m2
C.5.6kg - m2
D.2.5kg - m2
Solution
Torque = I α
[Iis moment of inertia motion the angular acceleration]
31.4 = 1 × 4p
I =
2.50 kg-m2
[Iis moment of inertia motion the angular acceleration]
31.4 = 1 × 4p
I =
2.50 kg-m2Create a free account to view solution
View Solution FreeMore Momentum and Collision Questions
An isolated particle of mass m is moving in horizontal plane (x-y), along x-axis, at a certain height above the ground. ...A ball of mass 2m impinges directly on a ball of mass m, which is at rest. If the velocity with which the larger ball im...If both the blocks as shown in the given arrangement are given together a horizontal velocity towards right. If acm be t...If the terminal speed of a sphere of gold (density = 19.5 kg/m3) is 0.2 m/s in a viscous liquid (density = 1.5 kg/m3), f...As shown in the figure a body of mass m moving vertically with speed 3 m/s hits a smooth fixed inclined plane and reboun...