Work, Power and EnergyHard
Question
A spring 40mm long is stretched by applying a force. If 10 N force is required to stretch the spring through one mm, then work done in stretching the spring through 40 mm is :
Options
A.24J
B.8 J
C.56 J
D.64 J
Solution
Force constant,
k =
= 104N/m
Work done =
kx2 = × 104 × 
= × 104 × 
= 8 joule
k =
= 104N/mWork done =
kx2 = × 104 × =
× 104 × = 8 jouleCreate a free account to view solution
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