Work, Power and EnergyHard
Question
A block of mass 0.50 kg is moving with a speed of 2.00 m/s on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is
Options
A.0.16 J
B.1.00 J
C.0.67 J
D.0.34 J
Solution
m1u1 + m2u2 = (m1 + m2)v
v = 2/3 m/s
Energy loss =
(0.5) × (2)2 - (1.5) × 
= 0.67 J
(Energy loss = 1/2(reduced mass)×Vrel)
v = 2/3 m/s
Energy loss =
(0.5) × (2)2 - (1.5) × = 0.67 J(Energy loss = 1/2(reduced mass)×Vrel)
Create a free account to view solution
View Solution FreeMore Work, Power and Energy Questions
Two bodies of masses 0.1 kg and 0.4 kg move towards each other with the velocities 1m/s and 0.1m/s respectively. After c...If the momentum of a certain body is increased by 50%, its kinetic energy will be increased by:-...A particle of mass m is initially at rest at the origin. It is subjected to a force and starts moving along the x-axis. ...The graph which represents the variation of mean kinetic energy of molecules with temperature toC is :-...A particle is moving in a circular path of radius a under the action of an attractive potential U = - k2r2. Its total en...