Work, Power and EnergyHard
Question
A block of mass 0.50 kg is moving with a speed of 2.00 m/s on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is
Options
A.0.16 J
B.1.00 J
C.0.67 J
D.0.34 J
Solution
m1u1 + m2u2 = (m1 + m2)v
v = 2/3 m/s
Energy loss =
(0.5) × (2)2 - (1.5) × 
= 0.67 J
(Energy loss = 1/2(reduced mass)×Vrel)
v = 2/3 m/s
Energy loss =
(0.5) × (2)2 - (1.5) × = 0.67 J(Energy loss = 1/2(reduced mass)×Vrel)
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