Momentum and CollisionHard
Question
In the given figure, the position-time graph of a particle of mass 0.1 kg is shown. The impulse at t = 2 sec is :
Options
A.0.2 kg msec-1
B.- 0.2 kg msec-1
C.0.1 kg msec-1
D.-0.4 kg msec-1
Solution
Impulse = mu - mv
= 0.1×
- m×0 [v = 0 after two seconds
= 0.2 kg m sec-1
= 0.1×
- m×0 [v = 0 after two seconds = 0.2 kg m sec-1
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