Basic Maths and Units and DimensionsMedium
Question
Using mass (m), length (L), time (T)and current (A)as fundamental quantities, the dimensions of permeability are :
Options
A.[M-1LT-2A]
B.[ML-2T-2A-1]
C.[MLT-2A-2]
D.[MLT-1A-1]
Solution
B = μni ; F = Bqv
F = μniqv ⇒ μ =
μ =
[n is no. of turns per unit lengh]
= MLA-2T-2
F = μniqv ⇒ μ =
μ =
[n is no. of turns per unit lengh]
= MLA-2T-2
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