VectorHard
Question
The side of a cube is (2.00 ± 0.01) cm. The volume and surface area of cube are respectively :
Options
A.(8.00 ± 0.12) cm3, (24.0 ± 0.24) cm2
B.(8.00 ± 0.01) cm3, (24.0 ± 0.1) cm2
C.(8.00 ± 0.04) cm3, (24.0 ± 0.06) cm2
D.(8.00 ± 0.03) cm3, (24.0 ± 0.02) cm2
Solution
Volume V = a3 = 8 cm3 .Also 
⇒ ᐃV = 3V 
= (3)(8) 
= 0.12 cm3
Therefore V = (8.00 ± 0.12) cm2 ; Surface Area A = 6a2 = 6 (2.00)2 = 24.0 cm2.
Also
⇒ ᐃA = 2A 
= 2(24.0) 
= 0.24. Therefore A = (24.0 ± 0.24) cm2
⇒ ᐃV = 3V = (3)(8) = 0.12 cm3Therefore V = (8.00 ± 0.12) cm2 ; Surface Area A = 6a2 = 6 (2.00)2 = 24.0 cm2.
Also
⇒ ᐃA = 2A = 2(24.0) = 0.24. Therefore A = (24.0 ± 0.24) cm2Create a free account to view solution
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