VectorHard
Question
The side of a cube is (2.00 ± 0.01) cm. The volume and surface area of cube are respectively :
Options
A.(8.00 ± 0.12) cm3, (24.0 ± 0.24) cm2
B.(8.00 ± 0.01) cm3, (24.0 ± 0.1) cm2
C.(8.00 ± 0.04) cm3, (24.0 ± 0.06) cm2
D.(8.00 ± 0.03) cm3, (24.0 ± 0.02) cm2
Solution
Volume V = a3 = 8 cm3 .Also 
⇒ ᐃV = 3V 
= (3)(8) 
= 0.12 cm3
Therefore V = (8.00 ± 0.12) cm2 ; Surface Area A = 6a2 = 6 (2.00)2 = 24.0 cm2.
Also
⇒ ᐃA = 2A 
= 2(24.0) 
= 0.24. Therefore A = (24.0 ± 0.24) cm2
⇒ ᐃV = 3V = (3)(8) = 0.12 cm3Therefore V = (8.00 ± 0.12) cm2 ; Surface Area A = 6a2 = 6 (2.00)2 = 24.0 cm2.
Also
⇒ ᐃA = 2A = 2(24.0) = 0.24. Therefore A = (24.0 ± 0.24) cm2Create a free account to view solution
View Solution FreeMore Vector Questions
″Parsec″ is the unit of :...What is the projection of 3î + 4on the y-axis ?...The sum of magnitudes of two forces acting at a point is 16N. If the resultant force is 8N and its direction is perpendi...Vector makes angle α, β and γ with the X, Y and Z axes respectively.Then sin2 α + sin2 β + sin2...Unpolarised light is incident from air on a plane surface of a material of refractive index 'μ'. At a particu...