Rotational MotionHard
Question
A circular platform is mounted on a frictionless vertical axle. Its radius R = 2 m and its moment ofinertia about the axle is 200 kg m2. It is initially at rest. A 50 kg man stands on the edge of theplatform and begins to walk along the edge at the speed of 1 ms-1 relative to the ground. Time takenby the man to complete one revolution is
Options
A.
B.π s
C.
D.2π s
Solution
Using conservation of angular momentum
Ipwp = ImWm
200 × Wp = 50(2)2 wm
wp = 1/2 rad/s
wm/p = wm - wp
= 1 rad/s
Time taken to complete one revolution is T
= 2π sec.
Ipwp = ImWm
200 × Wp = 50(2)2 wm
wp = 1/2 rad/s
wm/p = wm - wp
= 1 rad/sTime taken to complete one revolution is T
= 2π sec.Create a free account to view solution
View Solution FreeMore Rotational Motion Questions
A fly wheel is rotating about its axis at a constant angular velocity. If suddenly an object sticks to it on the rim, th...A cubical block of side L rests on a rough horizontal surface with coefficient of friction μ A horizontal force F i...A thin rod of length 4l, mass 4m is bent at the points as shown in the fig. What is the moment of inertia of the rod abo...In the above question, if the disc executes rotatory motion, its angular acceleration will be :-...In the above question, the value of its angular velocity after 2 seconds will be :-...