Rotational MotionHard
Question
A circular platform is mounted on a frictionless vertical axle. Its radius R = 2 m and its moment ofinertia about the axle is 200 kg m2. It is initially at rest. A 50 kg man stands on the edge of theplatform and begins to walk along the edge at the speed of 1 ms-1 relative to the ground. Time takenby the man to complete one revolution is
Options
A.
B.π s
C.
D.2π s
Solution
Using conservation of angular momentum
Ipwp = ImWm
200 × Wp = 50(2)2 wm
wp = 1/2 rad/s
wm/p = wm - wp
= 1 rad/s
Time taken to complete one revolution is T
= 2π sec.
Ipwp = ImWm
200 × Wp = 50(2)2 wm
wp = 1/2 rad/s
wm/p = wm - wp
= 1 rad/sTime taken to complete one revolution is T
= 2π sec.Create a free account to view solution
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