NEET | 2016Rotational MotionHard

Question

From a disc of radius R and mass M, a circular hole of diameter R, whose rim passes through the centre is cut. What is the moment of inertia of the remaining part of the disc about a perpendicular axis, passing through the centre?

Options

A.

15 MR2/32

B.

13 MR2/32

C.

11 MR2/32

D.

9 MR2/32

Solution


I=MR22-3σ2πR22R22
Where σ=MπR2
I=MR22-332MR2
I=1332MR2

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