Magnetic field due to currentHard
Question
A proton carrying 1 MeV kinetic energy is moving in a circular path of radius R in uniform magnetic field. What should be the energy of an α-particle to describe a circle of same radius in the samefield?
Options
A.4 MeV
B.2 MeV
C.1 MeV
D.0.5 MeV
Solution
For equal readius of proton and α-particle
Eα = Ep                  Eα = 1MeV
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