Question

Radius of circular path in magnetic field is given
by R = $\frac{\sqrt{3 Km}}{qB}$
where K = kinetic energy of particle
m = mass of particle
q = charge on particle
B = magnetic field intensity
R = radius of path
For electron
${\mathrm{r}}_{\mathrm{e}}=\frac{\sqrt{2 \mathrm{K} {\mathrm{m}}_{\mathrm{e}}}}{\mathrm{eB}}$  ...(i)
For proton
${\mathrm{r}}_{\mathrm{p}}=\frac{\sqrt{2 \mathrm{K} {\mathrm{m}}_{\mathrm{p}}}}{\mathrm{eB}}$  ...(ii)
For $\mathrm{Î\pm }$ particle
$r_{\mathrm{Î\pm }}=\frac{\sqrt{2K{m}_{\mathrm{Î\pm }}}}{q_{\mathrm{Î\pm }}B}=\frac{\sqrt{2K 4m_p}}{2eB}=\frac{\sqrt{2K{m}_p}}{eB}$ ...(iii)
as me < m_p so r_e < r_p = r_{$\mathrm{Î\pm }$}