ParabolaHard
Question
The axis of a parabola is along the line y = x and the distance of its vertex from origin is √2 and that from its focus is 2√2. If vertex and focus both lie in the first quadrant, then the equation of the parabola is
Options
A.(x + y)2 = (x - y - 2)
B.(x - y)2 = (x + y - 2)
C.(x - y)2 = 4 (x + y - 2)
D.(x - y)2 = 8 (x + y - 2)
Solution
Equation of directrix is x + y = 0.
Hence equation of the parabola is

Hence equation of parabola is
(x - y)2 = 8(x + y - 2).
Hence equation of the parabola is

Hence equation of parabola is
(x - y)2 = 8(x + y - 2).
Create a free account to view solution
View Solution FreeMore Parabola Questions
Tangents are drawn from the points on the line x - y + 3 = 0 to parabola y2 = 8x. Then the variable chords of contact pa...Length of the normal chord of the parabola, y2 = 4x, which makes an angle of with the axis of x is -...Consider the parabola $y^2 = 12x$ with its vertex at O. Let P be a point on the parabola and A be a point on the x-axis ...If a ≠ 0 and the line 2bx + 3cy + 4d = 0 passes through the points of intersection of the parabolas y2 = 4ax and x...If the line x - 1 = 0 is the directrix of the parabola y2 = kx - 8, then one of the values of k is...