ParabolaEasy
Question
The area of the region bounded by the parabola (y - 2)2 = x - 1, the tangent to the parabola at the point (2, 3) and the x-axis is
Options
A.3
B.6
C.9
D.12
Solution

Equation of tangent at (2, 3) to
(y - 2)2 = x - 1 is S1 = 0
⇒ x - 2y + 4 = 0
Required Area = Area of ᐃOCB + Area of OAPD – Area of ᐃPCD
=
= 4 +
- 1 = 4 - 9 - 18 + 15 - 1 = 28 - 19 = 9sq. units
(or)
Area =
(2y - 4 - y2 + 4y - 5)dy =
(- y2 + 6y - 5)dy = -
(3- y)2 dy
= 9 sq.unitsCreate a free account to view solution
View Solution FreeMore Parabola Questions
Let P be a moving point on the circle$$x^{2} + y^{2} - 6x - 8y + 21 = 0$$Then, the maximum distance of P from the vertex...Consider ellipse = 1 (a > b) & parabola y2 = 4A(x + 4), A > 0. If vertex of parabola coincideswith one focus of ellipse ...The length of the chord of the parabola y2 = x which is bisected at the point (2, 1) is -...Angle between y = e-x/2 and the parabola y2 = 4x is :...Locus of the intersection of the tangents at the ends of the normal chords of the parabola y2 = 4ax is -...