Trigonometric EquationHard
Question
The tangent to the curve y = ex drawn at the point (c, ec) intersects the line joining the points (c, - 1, ec-1) and (c + 1, ec+1)
Options
A.on the left of x = c
B.on the right of x = c
C.at no point
D.at all points
Solution
Slope of the line joining the points (c - 1, ec-1) and (c + 1, ec+1) is equal to
⇒ tangent to the curve y = ex will intersect the given line to the left of the line x = c.
Alternative
The equation of the tangent to the curve y = ex at (c, ec) is
y - ec = ec(x - c) ..... (1)
Equation of the line joining the given points is
y - ec-1 =
[x -(c - 1)] ..... (2)Eliminating y from (1) and (2), we get
[x - (c - 1)] [2 - (e - e-1)] = 2e-1
or x - c =
< 0 ⇒ x < c.⇒ the line (1) and (2) meet on the left of the line x = c.
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