Trigonometric EquationEasy
Question
If one of the lines of my2 + (1 - m2)xy - mx2 = 0 is a bisector of the angle between the lines xy = 0, then m is
Options
A.- 1/2
B.- 2
C.1
D.2
Solution
Equation of bisectors of lines xy = 0 are y = ± x
put y = ± x in my2 + (1 - m2)xy - mx2 = 0, we get (1 - m2) x2 = 0
⇒ m = ± 1.
put y = ± x in my2 + (1 - m2)xy - mx2 = 0, we get (1 - m2) x2 = 0
⇒ m = ± 1.
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
Let ƒ(x) = 7tan8x + 7tan6x − 3tan4x − 3tan2x for all x ∈ . Then the correct expression(s) is(are)...If cos-1 x - cos-1 = α then 4x2 - 4xy cos α + y2 is equal to...The general solution of tan 3x = 1 is -...The sum of all the integral values of $p$ such that the equation $3\sin^{2}x + 12cosx - 3 = p,x \in R$, has at least one...is equal...