Alkyl Halides and Aryl HalidesHard

Question

The reagent(s) for the following conversion,

is/are

Options

A.alcoholic KOH
B.alcoholic KOH followed by NaNH2
C.aqueous KOH followed by NaNH2
D.Zn/CH3OH

Solution


Because CH2 = CH - Br has partial C - Br double bond character, it requires more stronger base to remove HBr.
Hence(B) is correct.

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