Solid StateHard
Question
Structure of a mixed oxide is cubic close-packed (c.c.p). The cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a mono valent metal B. The formula of the oxide is:
Options
A.AB2O2
B.ABO2
C.A2BO2
D.A2B3O4
Solution
O2- makes c.c.p.
So No. of O2- = 4
And (1/4)th of tetrahedral void = (1/4) × 8 = 2, occupied by A2+
And octahedral voids = 4, occupied by B+
So formula is A2B4O4 on AB2O2
So No. of O2- = 4
And (1/4)th of tetrahedral void = (1/4) × 8 = 2, occupied by A2+
And octahedral voids = 4, occupied by B+
So formula is A2B4O4 on AB2O2
Create a free account to view solution
View Solution FreeMore Solid State Questions
If the radius of a metal atom is 2.00 (Ao) and its crystal structure in cubic close packed (fcc lattice), what is the vo...MgAl2O4, is found in the Spinal structure in which O2- ions constitute CCP lattice, Mg2+ ions occupy 1/8th of the Tetrah...Calcium titanate crystallizes in a cubic unit cell with titanium atoms at the corner of the cell, oxygen atoms in the mi...Which of the following expressions is correct in the case of a sodium chloride unit cell (edge length = a)...In a hypothetical solid, C atoms are found to form cubical close-packed lattice. A atoms occupy all tetrahedral voids an...