ParabolaHard
Question
Consider a branch of the hyperbola x2 - 2y2 - 2 √2x - 4√2y - 6 = 0 with vertex at the point A. Let B be one of the end points of its latus rectum. If C is the focus of the hyperbola nearest to the point A, then the area of the triangle ABC is
Options
A.
B.
C.
D.
Solution
Hyperbola is 
a = 2, b = √2
e =
Area =
a(e - 1) × 
⇒ Area =
.
a = 2, b = √2
e =
Area =
a(e - 1) × ⇒ Area =
.Create a free account to view solution
View Solution FreeMore Parabola Questions
The co-ordinates of a point on the parabola 2y = x2 which is nearest to the point (0, 3) is...The parabolas y2 = 4x and x2 = 4y divide the square region bounded by the lines x = 4, y = 4 and the coordinate axes. If...Let C be a circle and L a line on the same plane such that C and L do not intersect. Let P be a moving point such that t...The equation of the directrix of the parabola y2 + 4y + 4x + 2 = 0 is...A parabola passes through (1, 2) and (3, 4). The tangents drawn at these points intersect at (-6, 8), then the slope of ...