ParabolaHard
Question
Consider a branch of the hyperbola x2 - 2y2 - 2 √2x - 4√2y - 6 = 0 with vertex at the point A. Let B be one of the end points of its latus rectum. If C is the focus of the hyperbola nearest to the point A, then the area of the triangle ABC is
Options
A.
B.
C.
D.
Solution
Hyperbola is 
a = 2, b = √2
e =
Area =
a(e - 1) × 
⇒ Area =
.
a = 2, b = √2
e =
Area =
a(e - 1) × ⇒ Area =
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