ParabolaHard
Question
Consider a branch of the hyperbola x2 - 2y2 - 2 √2x - 4√2y - 6 = 0 with vertex at the point A. Let B be one of the end points of its latus rectum. If C is the focus of the hyperbola nearest to the point A, then the area of the triangle ABC is
Options
A.
B.
C.
D.
Solution
Hyperbola is 
a = 2, b = √2
e =
Area =
a(e - 1) × 
⇒ Area =
.
a = 2, b = √2
e =
Area =
a(e - 1) × ⇒ Area =
.Create a free account to view solution
View Solution FreeMore Parabola Questions
The triangle PQR of area ′A′ is inscribed in the parabola y2 = 4ax such that vertex P lies at the vertex of ...AB, AC are tangents to a parabola y2 = 4ax, p1 p2 and p3 are the lengths of the perpendiculars from A, B and C respectiv...PQ is a normal chord of the parabola y2 = 4ax at P, A being the vertex of the parabola. Through P a line is drawn parall...The equation of the directrix of the parabola y2 + 4y + 4x + 2 = 0 is...Locus of the intersection of the tangents at the ends of the normal chords of the parabola y2 = 4ax is -...