If at 298 K the bond energies of C-H, C-C, C = C and H-H bonds are respectively 414, 347, 615 and 43

Question

If at 298 K the bond energies of C-H, C-C, C = C and H-H bonds are respectively 414, 347, 615 and 435 kJ mol-1, the value of enthalpy change for the reaction H2C = CH2(g) + H2(g) &#8594; H3C - CH3(g) at 298 K will be

Accepted Answer

CH2 = CH2 (g) + H2(g) &#8594; CH3 - CH3 &#5123;H = 1(C = C) + 4(C - H) + 1(H-H) -1(C - C) - 6(C - H) = 1(C = C) + 1(H - H) - 1(C - C) - 2(C - H) = 615 + 435 - 347 - 2 &#215; 414 = 1050 - 1175 = - 125kJ.

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