Area under the curveHard
Question
If y = f(x) makes +ve intercept of 2 and 0 unit on x and y axes and encloses an area of 3/4 square unit with the axes then 
xf′(x) dx is
xf′(x) dx isOptions
A.3/2
B.1
C.5/4
D.-3/4
Solution
We have f(x) dx = 
; Now, xf′(x)dx = x f′(x)dx - f(x) dx
= [x f(x)]02 - = 2f(2)- = 0 - (∵f(2) = 0) = -
f(x) dx = ; Now, xf′(x)dx = x f′(x)dx - f(x) dx= [x f(x)]02 -
= 2f(2)- = 0 - (∵f(2) = 0) = - Create a free account to view solution
View Solution FreeMore Area under the curve Questions
Area enclosed by the curve y = sin x between x = 2nπ to x = 2(n +1)π is -...The area enclosed by the curve y2 + x4 = x2 is -...The area bounded by the parabola x2 = 4y, the x-axis and the line x = 4 is divided into two equal area by the line x = &...The whole area of the ellipse = 1 is-...Which one of the following is not a correct statements ?...