Area under the curveHard
Question
The area of the plane region bounded by the curves x + 2y2 = 0 and x + 3y2 = 1 is equal to
Options
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Solution
Solving the equations we get the points of intersection (-2, 1) and (-2, -1)
The bounded region is shown as shaded region.
The required area = 2
(1 - 3y2) - (-2y2) = 2
(1 - y2) dy = 2
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