Chemical Kinetics and Nuclear ChemistryHard
Question
For a first order reaction A → P, the temperature (T) dependent rate constant (k) was found to follow the equation log k = - (2000)
+ 60. The pre-exponential factor A and the activation energy Ea, respectively, are
+ 60. The pre-exponential factor A and the activation energy Ea, respectively, areOptions
A.1.0 × 106 s-1 and 9.2 kJmol-1
B.6.0 s-1 and 16.6 kJmol-1
C.1.0 × 106 s-1 and 16.6 kJmol-1
D.1.0 × 106 s-1 and 38.3 kJmol-1
Solution
Given, log K = 6 -
Since, log K = log A -
So, A = 106 sec-1 and Ea = 38.3 kJ/mole
Since, log K = log A -
So, A = 106 sec-1 and Ea = 38.3 kJ/moleCreate a free account to view solution
View Solution FreeTopic: Chemical Kinetics and Nuclear Chemistry·Practice all Chemical Kinetics and Nuclear Chemistry questions
More Chemical Kinetics and Nuclear Chemistry Questions
Purple of cassius is colloidal solution of :...The half-life of a radioactive isotope is three hours. If the initial mass of the isotope were 256 g, the mass of it rem...Correct order of rate of SN1 :-...The rate constant of a reaction is given by K = 2.1 ×1010 exp (-2700 / RT) it means that is :...Consider the following nuclear reactions The number of neutrons in the element L is...