ParabolaEasy
Question
Let L be a normal to the parabola y2 = 4x. If L passes through the point (9, 6), then L is given by
Options
A.y - x + 3 = 0
B.y + 3x - 33 = 0
C.y + x - 15 = 0
D.y - 2x + 12 = 0
Solution
y2 = 4x
Equation of normal is y = mx - 2m - m3.
It passes through (9, 6)
⇒ m3 - 7m + 6 = 0
⇒ m = 1, 2, - 3
⇒ y - x + 3 = 0, y + 3x - 33 = 0, y - 2x + 12 = 0.
Equation of normal is y = mx - 2m - m3.
It passes through (9, 6)
⇒ m3 - 7m + 6 = 0
⇒ m = 1, 2, - 3
⇒ y - x + 3 = 0, y + 3x - 33 = 0, y - 2x + 12 = 0.
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