FunctionHard
Question
Let f : [-1, 2] → [0, ∞) be a continuous function such that f(x) = f (1 - x) for all x ε [-1, 2]. Let R4
f(x)dx, and R2 be the area of the region bounded by y = f(x), x = -1, x = 2, and the x-axis. Then
f(x)dx, and R2 be the area of the region bounded by y = f(x), x = -1, x = 2, and the x-axis. ThenOptions
A.R1 = 2R2
B.R1 = 3R2
C.2R1 = R2
D.3R1 = R2
Solution
R1 =
f(x)dx =
(2 - 1 - x)f(2 - 1 - x)dx
=
(1 - x)f(1 - x) dx =
(1 - x)f(x)dx
Hence 2R1 =
f(x)dx = R2
f(x)dx =
(2 - 1 - x)f(2 - 1 - x)dx=
(1 - x)f(1 - x) dx =
(1 - x)f(x)dxHence 2R1 =
f(x)dx = R2Create a free account to view solution
View Solution FreeMore Function Questions
If f (x) = log and g(x) =, then f[g(x)] is equal to-...If f(x) = 2 sin x, g(x) = cos2x, then (f + g) =...If f : R → R, f(x) = ex and g : R → R, g(x) = 3x − 2 , then the value of (fog)-1(x) is equal to -...Which of the following pair of functions are identical -...Which of the following is an into function -...