Math miscellaneousHard
Question
If f(y) = ey, g(y) = y; y > and F(t) =
f(t - y)g (y) dy, then
f(t - y)g (y) dy, thenOptions
A.F(t) = 1 - e-t (1 + t)
B.F(t) = et - (1 + t)
C.F(t) = t et
D.F(t) = t e-t
Solution
F(t) =f(t - y) f(y) dy
=f(y)f(t - y)dy
=ey(t - y)dy
= xt - (1 + t).
Hence, (B) is the correct answer.
f(t - y) f(y) dy=
f(y)f(t - y)dy=
ey(t - y)dy= xt - (1 + t).
Hence, (B) is the correct answer.
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