Math miscellaneousHard
Question
If the system of linear equations
x + 2ay + az = 0
x + 3by + bz = 0
x + 4cy + cz = 0
has a non - zero solution, then a, b, c
x + 2ay + az = 0
x + 3by + bz = 0
x + 4cy + cz = 0
has a non - zero solution, then a, b, c
Options
A.are in A. P.
B.are in G.P.
C.are in H.P.
D.satisfy a + 2b + 3c = 0
Solution
Coefficient determinant =
= 0
⇒ b =
Hence, (C) is the correct answer
= 0⇒ b =
Hence, (C) is the correct answer
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