ParabolaEasy
Question
If a ≠ 0 and the line 2bx + 3cy + 4d = 0 passes through the points of intersection of the parabolas y2 = 4ax and x2 = 4ay , then
Options
A.d2 + (2b + 3c)2 = 0
B.d2 + (3b + 2c)2 = 0
C.d2 + (2b - 3c)2 = 0
D.d2 + (3b - 2c)2 = 0
Solution
Points of intersection of given parabolas are (0, 0) and (4a, 4a)
⇒ equation of line passing through these points is y = x
On comparing this line with the given line 2bx + 3cy + 4d = 0, we get
d = 0 and 2b + 3c = 0 ⇒ (2b + 3c)2 + d2 = 0.
⇒ equation of line passing through these points is y = x
On comparing this line with the given line 2bx + 3cy + 4d = 0, we get
d = 0 and 2b + 3c = 0 ⇒ (2b + 3c)2 + d2 = 0.
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