Set, Relation and FunctionHard
Question
A function y = f(x) has a second order derivative f″(x) = 6(x - 1). If its graph passes through the point (2, 1) and at that point the tangent to the graph is y = 3x - 5, then the function is
Options
A.(x - 1)2
B.(x - 1)3
C.(x + 1)3
D.(x + 1)2
Solution
f″(x) = 6(x - 1) ⇒ f′(x) = 3(x - 1)2 + c
and f′(2) = 3 ⇒ c = 0
⇒ f(x) = (x - 1)3 + k and f(2) = 1 ⇒ k = 0
⇒ f(x) = (x - 1)3.
and f′(2) = 3 ⇒ c = 0
⇒ f(x) = (x - 1)3 + k and f(2) = 1 ⇒ k = 0
⇒ f(x) = (x - 1)3.
Create a free account to view solution
View Solution FreeMore Set, Relation and Function Questions
If 0 ≤ [x] < 2 , - 1 ≤ [y] < 1 and 1 ≤ [z] < 3 where [·] denotes the greatest integer functio...Let A(h, k), B(1, 1) and C(2, 1) be the vertices of a right angled triangle with AC as its hypotenuse. If the area of th...Let S be a non-empty subset of R. Consider the following statement: P: There is a rational number x ∈ S such that ...If $\ln(a^b) = e^2$, then find the values of a and b....The Range of the fucntion y = is : -...