Set, Relation and FunctionHard
Question
A function y = f(x) has a second order derivative f″(x) = 6(x - 1). If its graph passes through the point (2, 1) and at that point the tangent to the graph is y = 3x - 5, then the function is
Options
A.(x - 1)2
B.(x - 1)3
C.(x + 1)3
D.(x + 1)2
Solution
f″(x) = 6(x - 1) ⇒ f′(x) = 3(x - 1)2 + c
and f′(2) = 3 ⇒ c = 0
⇒ f(x) = (x - 1)3 + k and f(2) = 1 ⇒ k = 0
⇒ f(x) = (x - 1)3.
and f′(2) = 3 ⇒ c = 0
⇒ f(x) = (x - 1)3 + k and f(2) = 1 ⇒ k = 0
⇒ f(x) = (x - 1)3.
Create a free account to view solution
View Solution FreeMore Set, Relation and Function Questions
If A, B and C are three sets such that A ∩ B = A ∩ C and A ∪ B = A ∪ C, then...Let R = {(3, 3), (6, 6), (9, 9), (12, 12), (6, 12), (3, 9), (3, 12), (3, 6)} be a relation on the set A = {3, 6, 9, 12} ...The set of all values of λ for which the system of linear equations :2x1 - 2x2 + x3 = λx12x1 - 3x2 + 2x3 = 	...The set S = {1, 2, 3, ...., 12) is to be partitioned into three sets A, B, C of equal size. Thus, A∪B∪C = S,...Let R be a relation on the set N of natural numbers defined by nRm ⇔ n is a factor of m (i.e. n | m). Then R is -...