Set, Relation and FunctionEasy
Question
Let A = {x1, x2,......, x7} and B = {y1, y2, y3} be two sets containing seven and three distinct elements respectively.Then the total number of functions f : A → B that are onto, if there exist exactly three elements x in A such that f(x) = y2, is equal to :
Options
A.14.7C3
B.16.7C3
C.14.7C2
D.12.7C2
Solution
Number of onto function such that exactly three elements in x → A such that f(x) = 1/2 is equal to
= 7C3.{24 − 2}
= 14.7C3
= 7C3.{24 − 2}
= 14.7C3
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