Quadratic EquationHard
Question
Let α and β be the roots of x2 - 6x - 2 = 0,, with α > β. If an = αn - βn for n ≥ 1. then the value of
is
is Options
A.1
B.2
C.3
D.4
Solution
an = αn - βn
α2 - 6α - 2 = 0
Multiply with α8 on both sides
⇒ α10 - 6α9 - 2α8 = 08 .......(i)
similarly β10 - 6β9 - 2β8 = 0 .......(ii)
From (i) and (ii)
⇒ α10 - β10 - 6(α9 - β9) = 2 (α8 - β8)
⇒ a10 - 6a9 =2a9 ⇒
α2 - 6α - 2 = 0
Multiply with α8 on both sides
⇒ α10 - 6α9 - 2α8 = 08 .......(i)
similarly β10 - 6β9 - 2β8 = 0 .......(ii)
From (i) and (ii)
⇒ α10 - β10 - 6(α9 - β9) = 2 (α8 - β8)
⇒ a10 - 6a9 =2a9 ⇒

Create a free account to view solution
View Solution FreeMore Quadratic Equation Questions
For what values of p, the roots of the equation 12(p + 2)x2 −12(2p − 1) x − 38p − 11 = 0 are ima...The greatest value of the function $f(x) = x^{4} - 6bx^{2} + b^{2}$ on the interval $\lbrack - 2,1\rbrack$ depending on ...Let p and q be real numbers such that p ≠ 0, P3 ≠ -q. If α and β are nonzero complex numbers satis...If x is real, then the values of the expression are not -...Let g(x) = cos x2, f(x) = x and α, β (α<β) be the roots of the quadratic equation 18x2...