Quadratic EquationEasy
Question
Consider the equation (cos θ + 2)(cos θ + 3)........(cos θ + (n +1)) = n!, where q ∈ [0, 10 π]. Then -
Options
A.Sum of the roots is 24π
B.Sum of the roots is 25π
C.Product of the roots is less than 1000π5
D.Product of the roots is greater than 1000π5
Solution
(cos θ + 2)(cos θ + 3).....(cos(θ) + (n +1))
= 1.2.3 ......... n is possible when
cos θ = - 1
θ = (2n + 1)π
θ = π, 3π, 5π, 7π, 9π
Product = (945)π5
= 1.2.3 ......... n is possible when
cos θ = - 1
θ = (2n + 1)π
θ = π, 3π, 5π, 7π, 9π
Product = (945)π5
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