Quadratic EquationHard

Question

Let two numbers have arithmetic mean 9 and geometric mean 4. Then these numbers are the roots of the quadratic equation

Options

A.x2 + 18x + 16 = 0
B.x2 - 18x - 16 = 0
C.x2 + 18x - 16 = 0
D.x2 - 18x + 16 = 0

Solution

Let numbers be a, b ⇒ a + b = 18, √ab = 4 ⇒ ab = 16, a and b are roots of the equation
⇒   x2 - 18x + 16 = 0.

Create a free account to view solution

View Solution Free
Topic: Quadratic Equation·Practice all Quadratic Equation questions

More Quadratic Equation Questions

The three roots of equation $x^{4} - px^{3} + qx^{2} - rx + s = 0$, where $p,q,r,s \in R$ and $s < 0$, are $tanA,tanB...Let $p$ and $q$ be real numbers such that the parabola $y = x^{2} - 2px + q$ has no common point with the x -axis. Let t...The possible value(s) of ' $p$ ' for which the equations $ax^{2} - px + ab = 0$ and $x^{2} - ax - bx + ab = 0$ may have ...The equation x - has...If α and β are the roots of the equation x2 + (√α) x + β = 0 then the values of α and &#9...