Quadratic EquationHard
Question
Let a > 0, b > 0 and c > 0. Then, both the roots of the equation ax2 + bx + c = 0.
Options
A.are real and negative
B.have negative real parts
C.have positive real parts
D.None of the above
Solution
Since, a, b, c > 0
and az2 + bx + c = 0
⇒
Case I When b2 - 4ac > 0
⇒
and
both roots, are negative.
Case II When b2 - 4ac < 0
⇒
ie, both toots are equal and negative
Case III When b2 - 4ac < 0
⇒
have negative real part.
∴ From sbove discussion both roots have negative real parts.
and az2 + bx + c = 0
⇒
Case I When b2 - 4ac > 0
⇒
and
both roots, are negative.Case II When b2 - 4ac < 0
⇒
ie, both toots are equal and negative Case III When b2 - 4ac < 0
⇒
have negative real part. ∴ From sbove discussion both roots have negative real parts.
Create a free account to view solution
View Solution FreeMore Quadratic Equation Questions
If α and β are the roots of the equation x2 - x + 1 = 0, then α2009 + β2009 =...Roots of 3x + 3−x = 10 / 3 are-...If the value of quadratic trinomial $ax^{2} - bx + c$ is an integer for $x = 0,x = 1$ and $x = 2$, then the valueof the ...If x be real then 2x2 + 5x − 3 > 0 if -If x be real then 2x2 + 5x − 3 > 0 if -...The number of points in (- ∞,∞), for which x2 - xsinx - cosx = 0, is...