Quadratic EquationHard
Question
Let a > 0, b > 0 and c > 0. Then, both the roots of the equation ax2 + bx + c = 0.
Options
A.are real and negative
B.have negative real parts
C.have positive real parts
D.None of the above
Solution
Since, a, b, c > 0
and az2 + bx + c = 0
⇒
Case I When b2 - 4ac > 0
⇒
and
both roots, are negative.
Case II When b2 - 4ac < 0
⇒
ie, both toots are equal and negative
Case III When b2 - 4ac < 0
⇒
have negative real part.
∴ From sbove discussion both roots have negative real parts.
and az2 + bx + c = 0
⇒
Case I When b2 - 4ac > 0
⇒
and
both roots, are negative.Case II When b2 - 4ac < 0
⇒
ie, both toots are equal and negative Case III When b2 - 4ac < 0
⇒
have negative real part. ∴ From sbove discussion both roots have negative real parts.
Create a free account to view solution
View Solution FreeMore Quadratic Equation Questions
Let g(x) = cos x2, f(x) = x and α, β (α<β) be the roots of the quadratic equation 18x2...If $\alpha$ and $\beta(\alpha < \beta)$ are the roots of the equation $( - 2 + \sqrt{3})(|\sqrt{x} - 3|) + (x - 6\sqr...The equation whose roots are is-...If 1 lies between the roots of the quadratic equation 3x2 - 3sinθ.x + 2sin2θ = 2, then range of ′θ&...If x2 − 11 x + a = 0 and x2 − 14 x + 2a = 0 have one common root then a is equal to -...