Straight LineHard
Question
Two points A and B move from rest along a straight line with constant acceleration f and f′ respectively. If A takes m sec. more than B and describes ′n′ units more than B in acquiring the same speed then
Options
A.(f - f′)m2 = ff′n
B.(f + f′)m2 = ff′n
C.
(f + f′)m = ff′n2
(f + f′)m = ff′n2D.(f + f′)n =
ff′m2
ff′m2Solution
v2 = 2f(d + n) = 2f′d
v = f′(t) = (m + t)f
liminate d and m we get
(f′ - f)n =
ff′m2.
v = f′(t) = (m + t)f
liminate d and m we get
(f′ - f)n =
ff′m2.Create a free account to view solution
View Solution FreeMore Straight Line Questions
Let PQR be a right angled isosceles , right angled at P(2, 1) If the equation of the lineQR is 2x + y = 3 then the equat...Let the angles made with the positive x -axis by two straight lines drawn from the point $P(2,3)$ and meeting the line $...If the vertices of a triangle have integral coordinates, then the triangle is -...If r is the geometric mean of p and q, then the line px + qy + r = 0 -...If origin and (3, 2) are contained in the same angle of the lines 2x + y - a = 0, x - 3y + a = 0, then ′a′ m...