Straight LineHard

Question

Given the four lines with the equations x + 2 y - 3 = 0, 3x + 4 y - 7 = 0 2x + 3y - 4 = 0, 4x + 5y -6 = 0 then

Options

A.they are all concurrent
B.they are the sides of a quadrilateral
C.only three lines are concurrent
D.None of the above

Solution

Given lines, x + 2y - 3 = 0 and 3x + 4y - 7 = 0 intersect at 91, 10 which does not satisfy 2x + 3y - 4 = 0 and 4x + 5y - 6 = 0 Also, 3x + 4 y - 7 = 0 and 2x + 3y - 4 = 0 intersect at (5,-2) which does not satisfy x + 2 y - 3 = 0 and 4x + 5y - 6 = 0.
Lastly, intersection point of x + 2 y - 3 = 0 and 2x + 3y - 4 = 0 is (-1, 2) which satisfy 4x + 5y - 6 = 0
Hence, only three lines are concurrent.

Create a free account to view solution

View Solution Free
Topic: Straight Line·Practice all Straight Line questions

More Straight Line Questions