FunctionHard

Question

Let f : R → R be a differentiable function having f(2) = 6, f′(2). Then dt equals

Options

A.24
B.36
C.12
D.18

Solution

dt
Applying L Hospital rule
[4f(x)2 f′(x)] = 4f(2)3f′(2)
= 4 × 63 × = 18.

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