Progression (Sequence and Series)Hard
Question
If x = 
where a, b, c are in A.P. and |a| < 1, |b|<1, |c|< 1, then x, y, z are in
where a, b, c are in A.P. and |a| < 1, |b|<1, |c|< 1, then x, y, z are inOptions
A.G.P.
B.A.P.
C.Arithmetic - Geometric Progression
D.H.P.
Solution
x = 
y =
z = c = 1 - 
a, b, c are in A.P.
2b = a + c
⇒ x, y, z are in H.P.
y =
z =
c = 1 - a, b, c are in A.P.
2b = a + c
⇒ x, y, z are in H.P.
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