Progression (Sequence and Series)Hard
Question
For a positive integer n let a(n) = 1 + 
, then
, thenOptions
A.a(100) ≤ 100
B.a(100) > 100
C.a(200) ≤ 100
D.a(200) > 100
Solution
Given, a(n) = 1 +
Thus, a (100) < 100,
Therefore, (a) is the answer
Again, a(n)
Therefore, a (200) >
> 100
Therefore, (d) is also the answer.
Thus, a (100) < 100,
Therefore, (a) is the answer
Again, a(n)
Therefore, a (200) >
> 100 Therefore, (d) is also the answer.
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