Differential EquationHard
Question
If a2 + b2 + c2 = - 2 and f(x) =
then f(x) is a polynomial of degree
then f(x) is a polynomial of degreeOptions
A.1
B.0
C.3
D.2
Solution
f(x) = 
Applying C1 → C1 + C2 + C3
=
∵ a2 + b2 + c2 + 2 = 0
f(x) =
; Applying R1 → R1 - R2 , R2 → R2 - R3
f(x) = (x - 1)2
Hence degree = 2.
Applying C1 → C1 + C2 + C3=
∵ a2 + b2 + c2 + 2 = 0f(x) =
; Applying R1 → R1 - R2 , R2 → R2 - R3f(x) = (x - 1)2
Hence degree = 2.
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