Differential EquationHard
Question
If y1(x) is a solution of the differential equation 
+ f(x) y = 0, then a solution of differential equation 
+ f(x) y = r (x) is
+ f(x) y = 0, then a solution of differential equation + f(x) y = r (x) is Options
A.
∫y1(x)dx
∫y1(x)dxB.y1 (x) 
dx
dxC.∫r(x)y1(x)dx
D.none of these
Solution
(i) 
+ f(x) y1 = 0 ⇒ f(x) = 
(ii)
. y = r(x)
⇒ 
y = y1
+ f(x) y1 = 0 ⇒ f(x) = (ii)
. y = r(x) ⇒ y = y1
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