Math miscellaneousHard
Question
Let P be the point (1, 0) and Q a point on the locus y2 = 8x. The locus of mid point of PQ is
Options
A.y2 - 4x + 2 = 0
B.y2 + 4x + 2 = 0
C.y2 + 4y + 2 = 0
D.y2 - 4y + 2 = 0
Solution
P = (1, 0)
Q = (h, k) such that k2 = 8h
Let(α, β) be the midpoint of PQ
α =
, β = 
2α - 1 = h 2β = k.
(2β)2 = 8 (2α - 1) ⇒ β2 = 4α - 2
⇒ y2 - 4x + 2 = 0.
Q = (h, k) such that k2 = 8h
Let(α, β) be the midpoint of PQ
α =
, β = 2α - 1 = h 2β = k.
(2β)2 = 8 (2α - 1) ⇒ β2 = 4α - 2
⇒ y2 - 4x + 2 = 0.
Create a free account to view solution
View Solution FreeMore Math miscellaneous Questions
If | x2 - x - 6 | = x + 2, then number of positive integral solutions of equation is :...The positive integer just greater than (1+0.0001)10000 is...Distance between two parallel planes 2x + y + 2z = 8 and 4x + 2y + 4z + 5 = 0 is :-...The value of the integral I = x(1 - x)n dx is...If x1, x2, ......,xn are any real numbers and n is any positive integer, then...