Trigonometric EquationHard

Question

equals

Options

A. sec1

B. cosec1

C.tan1

D. tan1

Solution

is equal to

⇒ Given limit is equal to value of integral

x sec²x²dx
or

2x sec x²dx =

sec²tdt [put x² = t]
= (tan)₀¹ = tan 1.

Create a free account to view solution

View Solution Free

Topic: Trigonometric Equation·Practice all Trigonometric Equation questions

More Trigonometric Equation Questions

The maximum distance from origin of a point on the curve x = a sin t - b siny = a cos t - b cos, both a, b > 0 is...For 0 , the solution(s) of cosec cosec = 4√2 is(are)...If tan α = and sin β = , where 0 < α, β < , then 2β is equal to-...A hyperbola, having the transverse axis of length 2 sinθ, is confocal with the ellipse 3x2 + 4y2 = 12. Then its equ...The solution of (2 cos x - 1) (3 + 2 cos x ) = 0 in the interval 0 ≤ θ ≤ 2π is -...