EllipseHard
Question
Area of the greatest rectangle that can be inscribed in the ellipse
= 1 is
= 1 isOptions
A.2 ab
B.ab
C.

D.

Solution

Area of rectangle ABCD = (2acosθ)
(2bsinθ) = 2absin2θ
⇒ Area of greatest rectangle is equal to 2ab
when sin2θ = 1.
Create a free account to view solution
View Solution FreeMore Ellipse Questions
Equation of the ellipse whose focus is (6,7) directrix is x + y + 2 = 0 and e = 1/ √3 is-...The equation ax2 + 2hxy + by2 + 2gx + 2fy + c = 0 represents an ellipse if-...The foci of the ellipse, 25 (x + 1)2 + 9 (y + 2)2 = 225, are at-...Let the line $y - x = 1$ intersect the ellipse $\frac{x^{2}}{2} + \frac{y^{2}}{1} = 1$ at the points A and B . Then the ...An ellipse is such that the length of the talus rectum is equal to the sum of the lengths of its semi principal axes. Th...