EllipseHard
Question
In an ellipse, the distance between its foci is 6 and minor axis is 8. Then its eccentricity is
Options
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Solution
2ae = 6 ⇒ ae = 3
2b = 8 ⇒ b = 4
b2 = a2(1 - e2)
16 = a2 - a2e2
a2 = 16 + 9 = 25
a = 5
∴ e =
2b = 8 ⇒ b = 4
b2 = a2(1 - e2)
16 = a2 - a2e2
a2 = 16 + 9 = 25
a = 5
∴ e =
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