EllipseHard
Question
If F1 & F2 are the feet of the perpendiculars from the foci S1 & S2 of an ellipse
= 1 on the tangent at any point P on the ellipse, then (S1F1). (S2F2) is equal to
Options
A.2
B.3
C.4
D.5
Solution
e = 
∴ S1 = ( √2, 0), S2 = (- √2, 0 )
Equation of tangent is y = mx +
S1F1 =
S2F2 =
Now (S1 F1) (S2F2) =
= 3.
∴ S1 = ( √2, 0), S2 = (- √2, 0 )
Equation of tangent is y = mx +
S1F1 =
S2F2 =
Now (S1 F1) (S2F2) =
Create a free account to view solution
View Solution FreeMore Ellipse Questions
If a > 2b > 0 then positive value of m for which y = mx - b is a common tangent tox2 + y2 = b2 and (x - a)2 + y2 = b2 is...In an ellipse the distance between its foci is 6 and its minor axis is 8. Then its eccentricity is-...If the ellipse = 1 meet the ellipse = 1 in four distinct points and a = b2 −10b + 25 then which of the following i...The equation of the ellipse (referred to its axes as the axes of x and y respectively) which passes through the point (&...The foci of the ellipse = 1 and the hyperbola coincide. Then the value of b2 is...