Trigonometric EquationHard
Question
[(x + π)3 + cos2(x + 3π)]dx is equal toOptions
A.
B.
C.
D.
Solution
I = 
[(x + π)3 + cos2(x + 3π)]dx
Put x + π = tI =[t3 + cos2 t]dt = 2
cos2t dt
=(1 + cos 2t)dt = 
+ 0
[(x + π)3 + cos2(x + 3π)]dxPut x + π = tI =
[t3 + cos2 t]dt = 2cos2t dt=
(1 + cos 2t)dt = + 0Create a free account to view solution
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